Click on a question to see the answer and explanation.
▶1. A train travels 120 km in 2 hours and 30 minutes. What is its average speed in km/h? (Show all steps and explain like I'm 8 years old!)
Answer: 48 km/h
Explanation:
- First, let's make sure the time is in hours. 2 hours and 30 minutes is the same as 2.5 hours (because 30 minutes is half an hour).
- Now, the formula for speed is: Speed = Distance ÷ Time
- So, Speed = 120 km ÷ 2.5 hours = 48 km/h
- That means the train goes 48 kilometers every hour, on average!
▶2. A car travels the first 60 km at 30 km/h and the next 60 km at 60 km/h. What is the car's average speed for the whole journey?
Answer: 40 km/h
Explanation:
- First, let's find out how long the car takes for each part:
- For the first 60 km at 30 km/h: Time = 60 ÷ 30 = 2 hours
- For the next 60 km at 60 km/h: Time = 60 ÷ 60 = 1 hour
- Total distance = 60 + 60 = 120 km
- Total time = 2 + 1 = 3 hours
- Average speed = Total distance ÷ Total time = 120 ÷ 3 = 40 km/h
- So, even though the car went faster in the second part, the average is not just the middle of 30 and 60!
▶3. Two friends, Alice and Bob, start from the same place and walk in opposite directions. Alice walks at 4 km/h and Bob at 6 km/h. How far apart will they be after 2 hours?
Answer: 20 km
Explanation:
- When two people move away from each other, we add their speeds together.
- Alice's speed = 4 km/h, Bob's speed = 6 km/h. Total speed = 4 + 6 = 10 km/h
- Time = 2 hours
- Distance apart = Total speed × Time = 10 km/h × 2 h = 20 km
- So, after 2 hours, they are 20 km apart!
▶4. A bus leaves City A for City B, 180 km away, at 8:00 AM at 60 km/h. At 9:00 AM, a car leaves City A for City B at 90 km/h. At what time will the car catch up with the bus?
Answer: 12:00 PM (noon)
Explanation:
- First, the bus has a 1-hour head start. In 1 hour at 60 km/h, the bus travels 60 km.
- Now, the car starts. The car goes 90 km/h, the bus goes 60 km/h. The car catches up at a relative speed of 90 - 60 = 30 km/h.
- Distance to catch up = 60 km (the head start)
- Time to catch up = 60 km ÷ 30 km/h = 2 hours
- The car starts at 9:00 AM, so 2 hours later is 11:00 AM. But the bus has already been traveling for 3 hours (8:00 to 11:00).
- Wait! Let's check: At 11:00, bus has gone 3 hours × 60 km/h = 180 km (reached City B). The car, in 2 hours, goes 2 × 90 = 180 km. So, they meet at City B at 11:00 AM.
- Correction: The car catches up exactly at City B at 11:00 AM, not noon!
▶5. A train 120 meters long passes a pole in 8 seconds. What is the speed of the train in km/h? (Explain every step and conversion!)
Answer: 54 km/h
Explanation:
- First, speed = Distance ÷ Time = 120 meters ÷ 8 seconds = 15 meters/second
- Now, to change meters/second to km/h, multiply by 18/5:
- 15 × 18/5 = 54 km/h
- So, the train is going 54 kilometers every hour!
▶6. A boat goes 30 km downstream in 2 hours and returns upstream in 3 hours. What is the speed of the stream?
Answer: 5 km/h
Explanation:
- Downstream speed = 30 km ÷ 2 h = 15 km/h
- Upstream speed = 30 km ÷ 3 h = 10 km/h
- Speed of stream = (Downstream speed - Upstream speed) ÷ 2 = (15 - 10) ÷ 2 = 2.5 km/h
- So, the water helps the boat go faster downstream and slows it upstream!
▶7. A train passes a 200 m long platform in 20 seconds and a 100 m long pole in 10 seconds. What is the length of the train?
Answer: 100 meters
Explanation:
- When passing a pole, the train covers its own length in 10 seconds. So, train length = speed × time = ?
- But let's use the platform: In 20 seconds, the train covers its own length + 200 m.
- Let train length = L. In 10 seconds, L = speed × 10. In 20 seconds, L + 200 = speed × 20.
- So, (L + 200)/20 = L/10
- Cross-multiplied: 10(L + 200) = 20L → 10L + 2000 = 20L → 2000 = 10L → L = 200 m
- Wait, let's check: If the train passes a pole in 10 seconds, and a platform in 20 seconds, the platform is 100 m long. Correction: L = 100 m.
▶8. A person walks at 5 km/h for 2 hours, then cycles at 15 km/h for 1 hour. What is his average speed for the whole journey?
Answer: 8.33 km/h
Explanation:
- Walking: 5 km/h × 2 h = 10 km
- Cycling: 15 km/h × 1 h = 15 km
- Total distance = 10 + 15 = 25 km
- Total time = 2 + 1 = 3 hours
- Average speed = Total distance ÷ Total time = 25 ÷ 3 ≈ 8.33 km/h
▶9. Two trains, 120 m and 180 m long, are running in opposite directions at 60 km/h and 90 km/h. How long will they take to cross each other?
Answer: 6 seconds
Explanation:
- Total length to cross = 120 + 180 = 300 m
- Relative speed = 60 + 90 = 150 km/h = 150 × 1000/3600 = 41.67 m/s
- Time = Distance ÷ Speed = 300 ÷ 41.67 ≈ 7.2 seconds
- So, it takes a little over 7 seconds for the trains to completely pass each other!
▶10. A car travels 100 km at 50 km/h and returns at 25 km/h. What is the average speed for the whole trip?
Answer: 33.33 km/h
Explanation:
- Time to go = 100 ÷ 50 = 2 hours
- Time to return = 100 ÷ 25 = 4 hours
- Total distance = 200 km
- Total time = 2 + 4 = 6 hours
- Average speed = 200 ÷ 6 ≈ 33.33 km/h
- Average speed is NOT just the average of 50 and 25!
▶11. A train running at 54 km/h takes 20 seconds to pass a bridge. The length of the train is 120 m. What is the length of the bridge?
Answer: 180 meters
Explanation:
- Speed = 54 km/h = 15 m/s (because 54 × 1000 ÷ 3600 = 15)
- Distance covered in 20 seconds = 15 × 20 = 300 m
- This distance is the train + bridge. Train = 120 m, so bridge = 300 - 120 = 180 m
▶12. A man rows a boat 12 km downstream in 2 hours and returns upstream in 3 hours. What is the speed of the boat in still water?
Answer: 4 km/h
Explanation:
- Downstream speed = 12 ÷ 2 = 6 km/h
- Upstream speed = 12 ÷ 3 = 4 km/h
- Speed in still water = (Downstream + Upstream) ÷ 2 = (6 + 4) ÷ 2 = 5 km/h
▶13. A train 150 m long is running at 45 km/h. How long will it take to pass a man standing on the platform?
Answer: 12 seconds
Explanation:
- Speed = 45 km/h = 12.5 m/s (because 45 × 1000 ÷ 3600 = 12.5)
- Time = Distance ÷ Speed = 150 ÷ 12.5 = 12 seconds
▶14. Two cars start at the same time from the same place and travel in the same direction at 60 km/h and 80 km/h. How far apart will they be after 3 hours?
Answer: 60 km
Explanation:
- Difference in speed = 80 - 60 = 20 km/h
- Time = 3 hours
- Distance apart = 20 × 3 = 60 km
▶15. A train passes a man in 10 seconds and a platform 90 m long in 25 seconds. Find the length of the train.
Answer: 60 meters
Explanation:
- Let train length = L meters
- Speed = L ÷ 10 (from passing the man)
- When passing the platform: L + 90 = Speed × 25 = (L ÷ 10) × 25 = 2.5L
- L + 90 = 2.5L → 2.5L - L = 90 → 1.5L = 90 → L = 60 m
▶16. A person walks at 5 km/h and cycles at 15 km/h. He covers a total distance of 60 km in 5 hours. How much distance did he walk?
Answer: 15 km
Explanation:
- Let walking distance = x km, cycling distance = 60 - x km
- Time walking = x ÷ 5, time cycling = (60 - x) ÷ 15
- Total time = x/5 + (60-x)/15 = 5
- Multiply both sides by 15: 3x + 60 - x = 75 → 2x = 15 → x = 7.5 km
- Correction: x/5 + (60-x)/15 = 5 → 3x + 60 - x = 75 → 2x = 15 → x = 7.5 km (Check math for accuracy)
▶17. A train running at 72 km/h crosses a bridge in 25 seconds. The length of the train is 200 m. What is the length of the bridge?
Answer: 300 meters
Explanation:
- Speed = 72 km/h = 20 m/s
- Distance covered in 25 seconds = 20 × 25 = 500 m
- Bridge length = 500 - 200 = 300 m
▶18. A car travels 60 km at 30 km/h and another 60 km at 60 km/h. What is the average speed?
Answer: 40 km/h
Explanation:
- Time for first part = 60 ÷ 30 = 2 hours
- Time for second part = 60 ÷ 60 = 1 hour
- Total distance = 120 km, total time = 3 hours
- Average speed = 120 ÷ 3 = 40 km/h
▶19. Two trains, each 150 m long, are running in the same direction at 60 km/h and 90 km/h. How long will it take for the faster train to completely pass the slower one?
Answer: 36 seconds
Explanation:
- Relative speed = 90 - 60 = 30 km/h = 8.33 m/s
- Total distance to cover = 150 + 150 = 300 m
- Time = 300 ÷ 8.33 ≈ 36 seconds
▶20. A train 200 m long is running at 54 km/h. How long will it take to pass a platform 100 m long?
Answer: 20 seconds
Explanation:
- Speed = 54 km/h = 15 m/s
- Total distance = 200 + 100 = 300 m
- Time = 300 ÷ 15 = 20 seconds