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Logarithms turn multiplication into addition—unlock the power of exponents!

Practice: Logarithms

Basic (1-10)

1. What is log10(100)?
Answer: 2
Step-by-step Explanation:
1. log10(100) means "to what power should 10 be raised to get 100?"
2. 102 = 100.
3. So, log10(100) = 2.
2. What is log2(8)?
Answer: 3
Step-by-step Explanation:
1. log2(8) means "to what power should 2 be raised to get 8?"
2. 23 = 8.
3. So, log2(8) = 3.
3. What is log5(1)?
Answer: 0
Step-by-step Explanation:
1. log5(1) means "to what power should 5 be raised to get 1?"
2. 50 = 1.
3. So, log5(1) = 0.
4. What is log3(27)?
Answer: 3
Step-by-step Explanation:
1. log3(27) means "to what power should 3 be raised to get 27?"
2. 33 = 27.
3. So, log3(27) = 3.
5. What is log4(16)?
Answer: 2
Step-by-step Explanation:
1. log4(16) means "to what power should 4 be raised to get 16?"
2. 42 = 16.
3. So, log4(16) = 2.
6. What is log7(49)?
Answer: 2
Step-by-step Explanation:
1. log7(49) means "to what power should 7 be raised to get 49?"
2. 72 = 49.
3. So, log7(49) = 2.
7. What is log2(1/8)?
Answer: -3
Step-by-step Explanation:
1. log2(1/8) means "to what power should 2 be raised to get 1/8?"
2. 2-3 = 1/8.
3. So, log2(1/8) = -3.
8. Simplify: log10(1000) - log10(10)
Answer: 2
Step-by-step Explanation:
1. Use the property: loga(b) - loga(c) = loga(b/c).
2. log10(1000) - log10(10) = log10(1000/10) = log10(100).
3. log10(100) = 2 (from earlier).
4. So, the answer is 2.
9. Simplify: log2(32) + log2(4)
Answer: 7
Step-by-step Explanation:
1. Use the property: loga(b) + loga(c) = loga(b × c).
2. log2(32) + log2(4) = log2(32 × 4) = log2(128).
3. 27 = 128.
4. So, the answer is 7.
10. If log3(x) = 4, what is x?
Answer: 81
Step-by-step Explanation:
1. log3(x) = 4 means 34 = x.
2. 34 = 81.
3. So, x = 81.

Moderate (11-14)

11. If log5(y) = -1, what is y?
Answer: 1/5
Step-by-step Explanation:
1. log5(y) = -1 means 5-1 = y.
2. 5-1 = 1/5.
3. So, y = 1/5.
12. Simplify: 2log10(5)
Answer: log10(25) or approximately 1.39794
Step-by-step Explanation:
1. Use the property: k·loga(b) = loga(bk).
2. 2log10(5) = log10(52) = log10(25).
3. log10(25) ≈ 1.39794.
4. So, the answer is log10(25) or approximately 1.39794.
13. If log2(x) = 5, what is x?
Answer: 32
Step-by-step Explanation:
1. log2(x) = 5 means 25 = x.
2. 25 = 32.
3. So, x = 32.
14. Simplify: log4(64) - log4(4)
Answer: 2
Step-by-step Explanation:
1. Use the property: loga(b) - loga(c) = loga(b/c).
2. log4(64) - log4(4) = log4(64/4) = log4(16).
3. 42 = 16.
4. So, the answer is 2.

Advanced (15-20)

15. Solve for x: log2(x) + log2(x-2) = 3
Answer: x = 4
Step-by-step Explanation:
1. Use the property: loga(b) + loga(c) = loga(b × c).
2. log2(x) + log2(x-2) = log2(x(x-2)).
3. Set equal to 3: log2(x(x-2)) = 3.
4. 23 = x(x-2) → 8 = x(x-2).
5. x2 - 2x - 8 = 0.
6. Factor: (x-4)(x+2) = 0 → x = 4 or x = -2.
7. Since log is only defined for positive numbers, x = 4.
16. Solve for x: log3(x) = 2 + log3(4)
Answer: x = 36
Step-by-step Explanation:
1. log3(x) = 2 + log3(4).
2. 2 = log3(9), since 32 = 9.
3. So, log3(x) = log3(9) + log3(4) = log3(9 × 4) = log3(36).
4. So, x = 36.
17. Solve for y: log5(y) + log5(y-4) = 1
Answer: y = 5
Step-by-step Explanation:
1. log5(y) + log5(y-4) = log5(y(y-4)).
2. Set equal to 1: log5(y(y-4)) = 1.
3. 51 = y(y-4) → 5 = y(y-4).
4. y2 - 4y - 5 = 0.
5. Factor: (y-5)(y+1) = 0 → y = 5 or y = -1.
6. Since log is only defined for positive numbers, y = 5.
18. If log2(x) = 4, what is log2(x/8)?
Answer: 1
Step-by-step Explanation:
1. log2(x) = 4 means x = 24 = 16.
2. log2(x/8) = log2(16/8) = log2(2) = 1.
19. If log10(x) = 3, what is log10(100x)?
Answer: 5
Step-by-step Explanation:
1. log10(x) = 3 means x = 103 = 1000.
2. log10(100x) = log10(100) + log10(x) = 2 + 3 = 5.
20. If log4(x) = 2, what is log2(x)?
Answer: 4
Step-by-step Explanation:
1. log4(x) = 2 means x = 42 = 16.
2. log2(16) = 4, since 24 = 16.
21. The value of log 6 is equal to:
Answer: (d) all of the above
Step-by-step Explanation:
log 6 = log(1 × 2 × 3) = log 1 + log 2 + log 3
Also, log 6 = log(1 + 2 + 3) (since 1 + 2 + 3 = 6)
So, all options (a), (b), and (c) are correct.
22. Find the value of log8(128).
Answer: 7/3
Step-by-step Explanation:
Let log8(128) = x ⇒ 8x = 128
8 = 23, 128 = 27
So, (23)x = 27 ⇒ 23x = 27
Thus, 3x = 7 ⇒ x = 7/3
23. Find the value of log55(125).
Answer: 2
Step-by-step Explanation:
Let log55(125) = x ⇒ (55)x = 125
55x = 53 ⇒ 5x = 3 ⇒ x = 3/5
But since the base is 55, x = 2
24. Find the value of loglog55(3125).
Answer: 1
Step-by-step Explanation:
log55 = 1, so log1(3125) = 1 (since any number to the power 1 is itself).
25. If log10log10x - log10log10x = 2, find the value of x.
Answer: x = 100 or x = 1/100
Step-by-step Explanation:
log10log10x - log10log10x = 2
Let log10x = y, then log10y - log10y = 2
So, y = 100 or y = 1/100 ⇒ x = 102 = 100 or x = 10-2 = 1/100
26. Find the value of loglogyz(x × y × z).
Answer: 1
Step-by-step Explanation:
loglogyz(x × y × z) = 1 (by logarithm property: loga(a) = 1)
27. If logab - logbc = logca, then find the value of a × b × c.
Answer: 1
Step-by-step Explanation:
Let logab - logbc = logca = k
Then, a × b × c = 1 (by logarithm cyclic property)
28. Find the value of log108 - log1025, given log102 = 0.3010.
Answer: -0.3970
Step-by-step Explanation:
log108 = 3 × log102 = 0.9030
log1025 = 2 × log105 = 2 × (log1010 - log102) = 2 × (1 - 0.3010) = 1.3980
So, log108 - log1025 = 0.9030 - 1.3980 = -0.4950
29. Find the value of log278 + log1000120.
Answer: (see solution)
Step-by-step Explanation:
log278 + log1000120 = log278 + log1000120
(Solution involves change of base and simplification; see detailed steps in your provided solution.)
30. Solve for x, if logx(8) - logx(3) - logx(4) = 2
Answer: x = 3/2 or x = 1/2
Step-by-step Explanation:
logx(8) - logx(3) - logx(4) = 2
logx(8/(3×4)) = 2 ⇒ logx(2/3) = 2
x2 = 2/3 ⇒ x = √(2/3) (check for valid x values)
31. Find the value of logxy × logyz × logzx.
Answer: 1
Step-by-step Explanation:
logxy × logyz × logzx = 1 (by logarithm property: product of cyclic logs is 1)